(x+1)*(x^2-2x+5)=0

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Solution for (x+1)*(x^2-2x+5)=0 equation: 


Simplifying
(x + 1)(x2 + -2x + 5) = 0

Reorder the terms:
(1 + x)(x2 + -2x + 5) = 0

Reorder the terms:
(1 + x)(5 + -2x + x2) = 0

Multiply (1 + x) * (5 + -2x + x2)
(1(5 + -2x + x2) + x(5 + -2x + x2)) = 0
((5 * 1 + -2x * 1 + x2 * 1) + x(5 + -2x + x2)) = 0
((5 + -2x + 1x2) + x(5 + -2x + x2)) = 0
(5 + -2x + 1x2 + (5 * x + -2x * x + x2 * x)) = 0
(5 + -2x + 1x2 + (5x + -2x2 + x3)) = 0

Reorder the terms:
(5 + -2x + 5x + 1x2 + -2x2 + x3) = 0

Combine like terms: -2x + 5x = 3x
(5 + 3x + 1x2 + -2x2 + x3) = 0

Combine like terms: 1x2 + -2x2 = -1x2
(5 + 3x + -1x2 + x3) = 0

Solving
5 + 3x + -1x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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